#!/bin/bash 

for p in  e p
do

for ((m=3;m<=6;m++))
do
for ((d=1;d<=31;d++))
do
D=`printf "%02d" $d` 
M=`printf "%02d" $m` 

`/bin/egrep "^$D\.$M\.1994" ${p}1994.txt > 1994/$M/${p}1994$M$D.txt`
#`/bin/egrep "^$D\.$M\.1994" ${p}1994.txt`

done
done
done